Scala Serialization

Fury supports all scala object serialization:

• case class serialization supported
• pojo/bean class serialization supported
• object singleton serialization supported
• collection serialization supported
• other types such as tuple/either and basic types are all supported too.

Scala 2 and 3 are both supported.

Install

To add a dependency on Fury scala for scala 2 with sbt, use the following:

libraryDependencies += "org.apache.fury" % "fury-scala_2.13" % "0.10.3"

To add a dependency on Fury scala for scala 3 with sbt, use the following:

libraryDependencies += "org.apache.fury" % "fury-scala_3" % "0.10.3"

Quict Start

case class Person(name: String, id: Long, github: String)
case class Point(x : Int, y : Int, z : Int)

object ScalaExample {
  val fury: Fury = Fury.builder().withScalaOptimizationEnabled(true).build()
  // Register optimized fury serializers for scala
  ScalaSerializers.registerSerializers(fury)
  fury.register(classOf[Person])
  fury.register(classOf[Point])

  def main(args: Array[String]): Unit = {
    val p = Person("Shawn Yang", 1, "https://github.com/chaokunyang")
    println(fury.deserialize(fury.serialize(p)))
    println(fury.deserialize(fury.serialize(Point(1, 2, 3))))
  }
}

Fury creation

When using fury for scala serialization, you should create fury at least with following options:

import org.apache.fury.Fury
import org.apache.fury.serializer.scala.ScalaSerializers

val fury = Fury.builder().withScalaOptimizationEnabled(true).build()

// Register optimized fury serializers for scala
ScalaSerializers.registerSerializers(fury)

Depending on the object types you serialize, you may need to register some scala internal types:

fury.register(Class.forName("scala.Enumeration.Val"))

If you want to avoid such registration, you can disable class registration by FuryBuilder#requireClassRegistration(false). Note that this option allow to deserialize objects unknown types, more flexible but may be insecure if the classes contains malicious code.

And circular references are common in scala, Reference tracking should be enabled by FuryBuilder#withRefTracking(true). If you don't enable reference tracking, StackOverflowError may happen for some scala versions when serializing scala Enumeration.

Note that fury instance should be shared between multiple serialization, the creation of fury instance is not cheap.

If you use shared fury instance across multiple threads, you should create ThreadSafeFury instead by FuryBuilder#buildThreadSafeFury() instead.

Serialize case object

case class Person(github: String, age: Int, id: Long)
val p = Person("https://github.com/chaokunyang", 18, 1)
println(fury.deserialize(fury.serialize(p)))
println(fury.deserializeJavaObject(fury.serializeJavaObject(p)))

Serialize pojo

class Foo(f1: Int, f2: String) {
  override def toString: String = s"Foo($f1, $f2)"
}
println(fury.deserialize(fury.serialize(Foo(1, "chaokunyang"))))

Serialize object singleton

object singleton {
}
val o1 = fury.deserialize(fury.serialize(singleton))
val o2 = fury.deserialize(fury.serialize(singleton))
println(o1 == o2)

Serialize collection

val seq = Seq(1,2)
val list = List("a", "b")
val map = Map("a" -> 1, "b" -> 2)
println(fury.deserialize(fury.serialize(seq)))
println(fury.deserialize(fury.serialize(list)))
println(fury.deserialize(fury.serialize(map)))

Serialize Tuple

val tuple = Tuple2(100, 10000L)
println(fury.deserialize(fury.serialize(tuple)))
val tuple = Tuple4(100, 10000L, 10000L, "str")
println(fury.deserialize(fury.serialize(tuple)))

Serialize Enum

Scala3 Enum

enum Color { case Red, Green, Blue }
println(fury.deserialize(fury.serialize(Color.Green)))

Scala2 Enum

object ColorEnum extends Enumeration {
  type ColorEnum = Value
  val Red, Green, Blue = Value
}
println(fury.deserialize(fury.serialize(ColorEnum.Green)))

Serialize Option

val opt: Option[Long] = Some(100)
println(fury.deserialize(fury.serialize(opt)))
val opt1: Option[Long] = None
println(fury.deserialize(fury.serialize(opt1)))